s^2-49s-330=0

Solution for s^2-49s-330=0 equation:

s^2-49s-330=0

a = 1; b = -49; c = -330;
Δ = b2-4ac
Δ = -492-4·1·(-330)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-61}{2*1}=\frac{-12}{2}
=-6
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+61}{2*1}=\frac{110}{2}
=55
$